proofs
Provedattentioninnovationexternal-review-3

Positive exponential secant: certified residual bound

For all Δ,x∈R\htmlData{mx=1}{\Delta, x \in \htmlData{mx=0}{\mathbb{R}}}, if 0<Δ0 \mathrel{\htmlData{mx=1}{<}} \htmlData{mx=0}{\Delta} and −Δ≤x∧x≤0\htmlData{mx=1}{-\htmlData{mx=0}{\Delta}} \mathrel{\htmlData{mx=3}{\leq}} \htmlData{mx=2}{x} \mathbin{\htmlData{mx=6}{\land}} \htmlData{mx=4}{x} \mathrel{\htmlData{mx=5}{\leq}} 0, then

e−Δ≤ex∧ex≤1+1−e−ΔΔ⋅x∧1+1−e−ΔΔ⋅x≤1∧0≤1+1−e−ΔΔ⋅x−ex∧1+1−e−ΔΔ⋅x−ex≤(x+Δ)⋅−x2∧(x+Δ)⋅−x2≤Δ28\begin{aligned} & \htmlData{mx=3}{e^{\htmlData{mx=2}{-\htmlData{mx=1}{\Delta}}}} \mathrel{\htmlData{mx=6}{\leq}} \htmlData{mx=5}{e^{\htmlData{mx=4}{x}}} \\ & \htmlData{mx=0}{\land} \htmlData{mx=8}{e^{\htmlData{mx=7}{x}}} \mathrel{\htmlData{mx=18}{\leq}} \htmlData{mx=17}{1 + \htmlData{mx=16}{\htmlData{mx=14}{\frac{\htmlData{mx=12}{1 - \htmlData{mx=11}{e^{\htmlData{mx=10}{-\htmlData{mx=9}{\Delta}}}}}}{\htmlData{mx=13}{\Delta}}} \cdot \htmlData{mx=15}{x}}} \\ & \htmlData{mx=0}{\land} \htmlData{mx=27}{1 + \htmlData{mx=26}{\htmlData{mx=24}{\frac{\htmlData{mx=22}{1 - \htmlData{mx=21}{e^{\htmlData{mx=20}{-\htmlData{mx=19}{\Delta}}}}}}{\htmlData{mx=23}{\Delta}}} \cdot \htmlData{mx=25}{x}}} \mathrel{\htmlData{mx=28}{\leq}} 1 \\ & \htmlData{mx=0}{\land} 0 \mathrel{\htmlData{mx=41}{\leq}} \htmlData{mx=40}{\htmlData{mx=37}{1 + \htmlData{mx=36}{\htmlData{mx=34}{\frac{\htmlData{mx=32}{1 - \htmlData{mx=31}{e^{\htmlData{mx=30}{-\htmlData{mx=29}{\Delta}}}}}}{\htmlData{mx=33}{\Delta}}} \cdot \htmlData{mx=35}{x}}} - \htmlData{mx=39}{e^{\htmlData{mx=38}{x}}}} \\ & \htmlData{mx=0}{\land} \htmlData{mx=53}{\htmlData{mx=50}{1 + \htmlData{mx=49}{\htmlData{mx=47}{\frac{\htmlData{mx=45}{1 - \htmlData{mx=44}{e^{\htmlData{mx=43}{-\htmlData{mx=42}{\Delta}}}}}}{\htmlData{mx=46}{\Delta}}} \cdot \htmlData{mx=48}{x}}} - \htmlData{mx=52}{e^{\htmlData{mx=51}{x}}}} \mathrel{\htmlData{mx=61}{\leq}} \htmlData{mx=60}{\frac{\htmlData{mx=59}{(\htmlData{mx=56}{\htmlData{mx=54}{x} + \htmlData{mx=55}{\Delta}}) \cdot \htmlData{mx=58}{-\htmlData{mx=57}{x}}}}{2}} \\ & \htmlData{mx=0}{\land} \htmlData{mx=68}{\frac{\htmlData{mx=67}{(\htmlData{mx=64}{\htmlData{mx=62}{x} + \htmlData{mx=63}{\Delta}}) \cdot \htmlData{mx=66}{-\htmlData{mx=65}{x}}}}{2}} \mathrel{\htmlData{mx=72}{\leq}} \htmlData{mx=71}{\frac{\htmlData{mx=70}{\htmlData{mx=69}{\Delta}^{2}}}{8}} \end{aligned}
What the notation means · or point at any symbol
RReal numbers
The real numbers: every point on the number line. (ℝ)
x ∈ TVariables
Δ, x range over real numbers: the statement must hold for every choice. ((Δ x : ℝ))
<Less than
0 is strictly smaller than Δ. (0 < Δ)
−xNegation
The negative of Δ. (-Δ)
≤At most
−Δ is less than or equal to x. (-Δ ≤ x)
∧And
Both hold: −Δ ≤ x, and x ≤ 0. (-Δ ≤ x ∧ x ≤ 0)
eˣExponential function
e raised to the power −Δ, where e ≈ 2.718. (Real.exp (-Δ))
+Addition
1 plus (1 − exp(−Δ))/Δ · x. (1 + ((1 - Real.exp (-Δ)) / Δ) * x)
·Multiplication
(1 − exp(−Δ))/Δ times x. (((1 - Real.exp (-Δ)) / Δ) * x)
a/bDivision
1 − exp(−Δ) divided by Δ. In Lean, dividing by 0 gives 0. ((1 - Real.exp (-Δ)) / Δ)
-Subtraction
1 minus exp(−Δ). On ℕ, Lean's subtraction stops at 0: 2 − 5 = 0. (1 - Real.exp (-Δ))
aᵇPower
Δ raised to the power 2. (Δ ^ 2)

For positive interval width and x in [-width,0], proves exponential positivity via its endpoint, chord majorization, upper bound one, and residual bounded by the interpolation parabola and width squared over eight.

How it was proved

Proved
6 October 2026
By
Ajax, with the agent “Baguette math & proofs (Claude Code, 2026-10-03)”
Checked by
Lean's kernel (Lean 4.33.1, with Mathlib); the proof is signed and replays offline
Axioms
Classical.choice, Quot.sound, propext
Proof
51 lines of Lean
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