proofs
Proveddrift-lawdecodeinnovationreview-response

Innovation variance arithmetic: 2e^{2Δ}·(F(1−e^{−Δ}))² = 2F²(e^Δ − 1)²

For all F,Δ∈R\htmlData{mx=1}{F, \Delta \in \htmlData{mx=0}{\mathbb{R}}}:

2e2Δ⋅(F⋅(1−e−Δ))2=2⋅F2⋅(eΔ−1)2\begin{aligned} & \htmlData{mx=12}{\htmlData{mx=4}{2\htmlData{mx=3}{e^{\htmlData{mx=2}{2\htmlData{mx=1}{\Delta}}}}} \cdot \htmlData{mx=11}{(\htmlData{mx=10}{\htmlData{mx=5}{F} \cdot (\htmlData{mx=9}{1 - \htmlData{mx=8}{e^{\htmlData{mx=7}{-\htmlData{mx=6}{\Delta}}}}})})^{2}}} \\ & \quad \htmlData{mx=0}{=} \htmlData{mx=20}{\htmlData{mx=15}{2 \cdot \htmlData{mx=14}{\htmlData{mx=13}{F}^{2}}} \cdot \htmlData{mx=19}{(\htmlData{mx=18}{\htmlData{mx=17}{e^{\htmlData{mx=16}{\Delta}}} - 1})^{2}}} \end{aligned}
What the notation means · or point at any symbol
RReal numbers
The real numbers: every point on the number line. (ℝ)
x ∈ TVariables
F, Δ range over real numbers: the statement must hold for every choice. ((F Δ : ℝ))
=Equality
2 · exp(2 · Δ) · (F · (1 − exp(−Δ)))^2 and 2 · F^2 · (exp(Δ) − 1)^2 are the same. (2 * Real.exp (2 * Δ) * (F * (1 - Real.e…)
eˣExponential function
e raised to the power 2 · Δ, where e ≈ 2.718. (Real.exp (2 * Δ))
·Multiplication
2 times Δ. (2 * Δ)
aᵇPower
F · (1 − exp(−Δ)) raised to the power 2. ((F * (1 - Real.exp (-Δ))) ^ 2)
-Subtraction
1 minus exp(−Δ). On ℕ, Lean's subtraction stops at 0: 2 − 5 = 0. (1 - Real.exp (-Δ))
−xNegation
The negative of Δ. (-Δ)

Combines the reward bound F(1 − a_min) with a_min = e^{−Δ} and the second moment E[T²] ≤ 2e^{2Δ} of the geometric stopping time into the variance bound 2F²(e^Δ − 1)² of the innovation estimator, which vanishes quadratically in the drift oscillation. Suggested by an external reviewer (2026-10-05).

How it was proved

Proved
5 October 2026
By
Ajax, with the agent “Baguette math & proofs (Claude Code, 2026-10-03)”
Checked by
Lean's kernel (Lean 4.33.1, with Mathlib); the proof is signed and replays offline
Axioms
Classical.choice, Quot.sound, propext
Proof
16 lines of Lean
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