proofs
Proveddrift-lawdecodeinnovationreview-response

Stopped-sum unbiasedness, geometric step: Σ'_{i≥0} (1−p)^i·(p·c) = c for 0 < p ≤ 1

For all p,c∈R\htmlData{mx=1}{p, c \in \htmlData{mx=0}{\mathbb{R}}}, if 0<p0 \mathrel{\htmlData{mx=1}{<}} \htmlData{mx=0}{p} and p≤1\htmlData{mx=0}{p} \mathrel{\htmlData{mx=1}{\leq}} 1, then

∑i∈N(1−p)i⋅(p⋅c)=c\htmlData{mx=9}{\sum_{i \in \htmlData{mx=0}{\mathbb{N}}} \htmlData{mx=8}{\htmlData{mx=4}{(\htmlData{mx=2}{1 - \htmlData{mx=1}{p}})^{\htmlData{mx=3}{i}}} \cdot (\htmlData{mx=7}{\htmlData{mx=5}{p} \cdot \htmlData{mx=6}{c}})}} \mathrel{\htmlData{mx=11}{=}} \htmlData{mx=10}{c}
What the notation means · or point at any symbol
RReal numbers
The real numbers: every point on the number line. (ℝ)
x ∈ TVariables
p, c range over real numbers: the statement must hold for every choice. ((p c : ℝ))
<Less than
0 is strictly smaller than p. (0 < p)
≤At most
p is less than or equal to 1. (p ≤ 1)
∑'Infinite sum
Add up (1 − p)^i · (p · c) for every i in ℕ. (∑' i : ℕ, (1 - p) ^ i * (p * c))
=Equality
∑' i, (1 − p)^i · (p · c) and c are the same. (∑' i : ℕ, (1 - p) ^ i * (p * c) = c)
NNatural numbers
The natural numbers 0, 1, 2, …. In Lean they start at 0. (ℕ)
aᵇPower
1 − p raised to the power i. ((1 - p) ^ i)
-Subtraction
1 minus p. On ℕ, Lean's subtraction stops at 0: 2 − 5 = 0. (1 - p)
·Multiplication
p times c. (p * c)

The series step of the innovation estimator's unbiasedness: trial i contributes with probability (1−p)^{i−1} (not yet accepted) and has reward mean p(o − m), so the expected total is (o − m). Suggested by an external reviewer (2026-10-05).

How it was proved

Proved
5 October 2026
By
Ajax, with the agent “Baguette math & proofs (Claude Code, 2026-10-03)”
Checked by
Lean's kernel (Lean 4.33.1, with Mathlib); the proof is signed and replays offline
Axioms
Classical.choice, Quot.sound, propext
Proof
17 lines of Lean
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