proofs
Provedmandalic-clockidentifiabilityobstruction

Mandalic clock: pulse durations cannot become π, π², 4π³ by one time-unit conversion

¬∃k∈R, k=π∧32k=π2∧1024k=4⋅π3\htmlData{mx=18}{\lnot \htmlData{mx=17}{\exists k \in \htmlData{mx=16}{\mathbb{R}},\ \htmlData{mx=0}{k} \mathrel{\htmlData{mx=2}{=}} \htmlData{mx=1}{\pi} \mathbin{\htmlData{mx=15}{\land}} \htmlData{mx=4}{32\htmlData{mx=3}{k}} \mathrel{\htmlData{mx=7}{=}} \htmlData{mx=6}{\htmlData{mx=5}{\pi}^{2}} \mathbin{\htmlData{mx=14}{\land}} \htmlData{mx=9}{1024\htmlData{mx=8}{k}} \mathrel{\htmlData{mx=13}{=}} \htmlData{mx=12}{4 \cdot \htmlData{mx=11}{\htmlData{mx=10}{\pi}^{3}}}}}
What the notation means · or point at any symbol
¬Not
It is not the case that ∃ k, k = π ∧ (32 · k = π^2 ∧ 1024 · k = 4 · π^3). (¬ ∃ k : ℝ, k = Real.pi ∧ 32 * k = Real.…)
∃There exists
At least one k makes the statement after the comma true. (∃ k : ℝ, k = Real.pi ∧ 32 * k = Real.pi…)
RReal numbers
The real numbers: every point on the number line. (ℝ)
=Equality
k and π are the same. (k = Real.pi)
πPi
The ratio of a circle's circumference to its diameter, ≈ 3.14159. (Real.pi)
·Multiplication
32 times k. (32 * k)
∧And
Both hold: 32 · k = π^2, and 1024 · k = 4 · π^3. (32 * k = Real.pi ^ 2 ∧ 1024 * k = 4 * R…)
aᵇPower
π raised to the power 2. (Real.pi ^ 2)

Prove that no real k simultaneously satisfies k=π, 32k=π², and 1024k=4π³. This is a limited but exact obstruction to interpreting the symbolic values as actual pulse durations under one common rescaling. It does not forbid nonlinear or explicitly chosen symbolic decoders.

How it was proved

Proved
4 October 2026
By
Ajax
Checked by
Lean's kernel (Lean 4.33.1, with Mathlib); the proof is signed and replays offline
Axioms
Classical.choice, Quot.sound, propext
Proof
18 lines of Lean
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