proofs
Provedalphabaguettebaguette-zv2

An int32 grid of 2⁻³⁰ rounds a typical second moment 10⁻¹² to zero; a 2⁻⁶⁰ grid keeps it at ≥ 10⁶ ulps

⌊11012⋅230⌋=0∧106≤11012⋅260\htmlData{mx=5}{\left\lfloor \htmlData{mx=4}{\htmlData{mx=2}{\htmlData{mx=1}{\frac{1}{\htmlData{mx=0}{10^{12}}}}} \cdot \htmlData{mx=3}{2^{30}}} \right\rfloor} \mathrel{\htmlData{mx=6}{=}} 0 \mathbin{\htmlData{mx=15}{\land}} \htmlData{mx=8}{\htmlData{mx=7}{10^{6}}} \mathrel{\htmlData{mx=14}{\leq}} \htmlData{mx=13}{\htmlData{mx=11}{\htmlData{mx=10}{\frac{1}{\htmlData{mx=9}{10^{12}}}}} \cdot \htmlData{mx=12}{2^{60}}}
What the notation means · or point at any symbol
⌊x⌋Floor
The largest integer not above 1/10^12 · 2^30. (⌊(1 / 10 ^ 12 : ℝ) * 2 ^ 30⌋)
=Equality
⌊1/10^12 · 2^30⌋ and 0 are the same. (⌊(1 / 10 ^ 12 : ℝ) * 2 ^ 30⌋ = 0)
∧And
Both hold: ⌊1/10^12 · 2^30⌋ = 0, and 10^6 ≤ 1/10^12 · 2^60. (⌊(1 / 10 ^ 12 : ℝ) * 2 ^ 30⌋ = 0 ∧ (10 …)
(x : T)As real numbers
1/10^12 read as an element of real numbers. Mathematicians leave this implicit; Lean needs it to know which kind of number is meant. ((1 / 10 ^ 12 : ℝ))
·Multiplication
1/10^12 times 2^30. ((1 / 10 ^ 12 : ℝ) * 2 ^ 30)
a/bDivision
1 divided by 10^12. In Lean, dividing by 0 gives 0. (1 / 10 ^ 12)
aᵇPower
10 raised to the power 12. (10 ^ 12)
≤At most
10^6 is less than or equal to 1/10^12 · 2^60. ((10 ^ 6 : ℝ) ≤ (1 / 10 ^ 12 : ℝ) * 2 ^ …)

Formal record of review S6: ⌊10⁻¹²·2³⁰⌋ = 0 (the v1 plan's moment format would have zeroed v and made Adam's direction m/ε explode), while 10⁻¹²·2⁶⁰ ≥ 10⁶ (relative precision ≤ 10⁻⁶ by bz2-moment-resolution). Part of 'Baguette-Z v2' (revision after the hostile review).

How it was proved

Proved
3 October 2026
By
Ajax, with the agent “Baguette math & proofs (Claude Code, 2026-10-03)”
Checked by
Lean's kernel (Lean 4.33.1, with Mathlib); the proof is signed and replays offline
Axioms
Classical.choice, Quot.sound, propext
Proof
15 lines of Lean
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