proofs
Provedalphabaguettebaguette-zoptimizer

Baguette's master weights stay within max(|θ₀|, 730) for an unbounded run

For all C∈R\htmlData{mx=1}{C \in \htmlData{mx=0}{\mathbb{R}}}, if 0≤C0 \mathrel{\htmlData{mx=1}{\leq}} \htmlData{mx=0}{C} and C2<53\htmlData{mx=1}{\htmlData{mx=0}{C}^{2}} \mathrel{\htmlData{mx=2}{<}} 53, then

C1−910110<730∧730<210\htmlData{mx=5}{\frac{\htmlData{mx=3}{\frac{\htmlData{mx=0}{C}}{\htmlData{mx=2}{1 - \htmlData{mx=1}{\frac{9}{10}}}}}}{\htmlData{mx=4}{\frac{1}{10}}}} \mathrel{\htmlData{mx=6}{<}} 730 \mathbin{\htmlData{mx=10}{\land}} \htmlData{mx=7}{730} \mathrel{\htmlData{mx=9}{<}} \htmlData{mx=8}{2^{10}}
What the notation means · or point at any symbol
RReal numbers
The real numbers: every point on the number line. (ℝ)
≤At most
0 is less than or equal to C. (0 ≤ C)
aᵇPower
C raised to the power 2. (C ^ 2)
<Less than
C^2 is strictly smaller than 53. (C ^ 2 < 53)
∧And
Both hold: C/(1 − 9/10)/(1/10) < 730, and 730 < 2^10. (C / (1 - 9 / 10) / (1 / 10) < 730 ∧ (73…)
-Subtraction
1 minus 9/10. On ℕ, Lean's subtraction stops at 0: 2 − 5 = 0. (1 - 9 / 10)
a/bDivision
9 divided by 10. In Lean, dividing by 0 gives 0. (9 / 10)
(x : T)As real numbers
730 read as an element of real numbers. Mathematicians leave this implicit; Lean needs it to know which kind of number is meant. ((730 : ℝ))

With per-step direction ≤ C/(1−β₁) < 73 (C < 7.3) and decay a = lr·0.1, the uniform box radius ηK/a = K/0.1 is below 730. Every master weight, gain and embedding coordinate of Baguette-Z fits in 10 integer bits for all time. Part of the plan 'Baguette-Z: closed-loop certified integer-state training'.

How it was proved

Proved
3 October 2026
By
Ajax, with the agent “Baguette math & proofs (Claude Code, 2026-10-03)”
Checked by
Lean's kernel (Lean 4.33.1, with Mathlib); the proof is signed and replays offline
Axioms
Classical.choice, Quot.sound, propext
Proof
16 lines of Lean
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